UPSC ESIC PA Online Form 2024 (323 Posts)

UPSC ESIC PA Recruitment 2024

Post Name – Personal Assistant

(Union Public Service Commission)



Start Date – 07-03-2024

Last Date – 27-03-2024

Fee Payment Last Date – 27-03-2024

Admit Card – Notify later

Exam Date – Notify Later


General/OBC /EWS – Rs. 100/-

SC/ST/PWD – Rs. 0/-

Fee can be paid only online through Net Banking, Credit or Debit cards


All India


(As on 01-08-2024)

Minimum Age – 18 Years

Maximum Age – 30 Years

Age Relaxation: As Per Rules

Total Posts :323 Posts

Post DescriptionUPSC Union Public Service Commission is inviting online applications for Personal Assistant for 323 posts. Interested people meet all the eligibility criteria, apply online

Details Of Recruitment Of UPSC ESIC Personal Assistant Online Form 2024

Posts NamePersonal Assistant

Number Of Posts323 Posts

Category Wise Posts

General – 132 Posts

OBC – 87 Posts

SC – 48 Posts

ST – 24 Posts

EWS – 32 Posts

Pay Scale Level 7

Education QualificationGraduate Degree From Recognized University And Dictation for 10 minutes with  120 WPM Speed in Stenography And Transcription Time for the dictation taken as per 50 minutes (English) / 65 minutes (Hindi) (Only on Computer).

How to Apply Online UPSC ESIC PA Online Form 2024Candidates can apply through link provided below or they can also apply through official site of the Union Public Service Commission before 27/March/2024.

Required Documents For Online Application

Educational Mark sheet And Certificates

Aadhar Card / Pan Card

Passport Size Photo


Selection Mode

Written Exam

Skill Test

Merit List

Online Apply

Click Here

Download Notification

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Download Short Notice

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Join Telegram

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Official website

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