UPSC ESIC PA Recruitment 2024Post Name – Personal Assistant(Union Public Service Commission) | |||||
WWW.SARKARIUJALA.COM | |||||
IMPORTANT DATESStart Date – 07-03-2024 Last Date – 27-03-2024 Fee Payment Last Date – 27-03-2024 Admit Card – Notify later Exam Date – Notify Later | FEE DETAILS• General/OBC /EWS – Rs. 100/- • SC/ST/PWD – Rs. 0/- Fee can be paid only online through Net Banking, Credit or Debit cards | ||||
JOB LOCATIONAll India | AGE LIMIT(As on 01-08-2024) Minimum Age – 18 Years Maximum Age – 30 Years Age Relaxation: As Per Rules | ||||
Total Posts :323 Posts | |||||
Post Description – UPSC Union Public Service Commission is inviting online applications for Personal Assistant for 323 posts. Interested people meet all the eligibility criteria, apply online Details Of Recruitment Of UPSC ESIC Personal Assistant Online Form 2024Posts Name –Personal Assistant Number Of Posts – 323 Posts Category Wise Posts – General – 132 Posts OBC – 87 Posts SC – 48 Posts ST – 24 Posts EWS – 32 Posts Pay Scale – Level 7 Education Qualification – Graduate Degree From Recognized University And Dictation for 10 minutes with 120 WPM Speed in Stenography And Transcription Time for the dictation taken as per 50 minutes (English) / 65 minutes (Hindi) (Only on Computer). How to Apply Online UPSC ESIC PA Online Form 2024– Candidates can apply through link provided below or they can also apply through official site of the Union Public Service Commission before 27/March/2024. Required Documents For Online Application – Educational Mark sheet And Certificates Aadhar Card / Pan Card Passport Size Photo Signature Selection Mode – Written Exam Skill Test Merit List | |||||
Important Links | |||||
Online Apply | Click Here | ||||
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